Two cyclists start at the same point and travel in opposite directions. one cyclist travels 10 /mi h slower than the other. if the two cyclists are 96mi apart after 4 hours, what is the rate of each cyclist?
We write the cinematic equation for each cyclist.  We have then:  Cyclist A:  ra = v * t  Cyclist B:  rb = - (v-10) * t  After 4 hours we have:  ra-rb = 4v - (-4 (v-10))  96 = 4v - (-4 (v-10))  Rewriting:  96 = 4v + 4 (v-10)  96 = 4v + 4v - 40  96 = 8v - 40  v = (96 + 40) / (8)  v = 17 mph  Cyclist A: v = 17mph  Cyclist B: v-10 = 17-10 = 7mhp  Answer:  the rate of each cyclist is:  Cyclist A: v = 17mph  Cyclist B: v-10 = 7mhp
