Respuesta :
average rate of reaction of H2 over this time is calculated as
initial concentration of H2 minus final concentration of H2
That is
{(0.35mol/l -0.12mol/l) / 50Â sec}= 4.6 x 10 ^-3Â mol/l/sec
Â
initial concentration of H2 minus final concentration of H2
That is
{(0.35mol/l -0.12mol/l) / 50Â sec}= 4.6 x 10 ^-3Â mol/l/sec
Â
1) Balanced chemical reaction: 3Hâ + Nâ â 2NHâ.
câ(Hâ) = 0.35 mol/L; initial concentration of hydrogen gas.
câ(Hâ) = 0.12 mol/L; concentration of hydrogen after 50 seconds.
Ît = 50 s.
the average rate of reaction = 1/3 ¡ (Îc(Hâ)/Ît).
the average rate of reaction of hydrogen = 1/3 ¡ ((câ(Hâ)-câ(Hâ))/Ît).
the average rate of reaction = 1/3 ¡ (0.12 mol/L - 0.35 mol/L) / 50 s.
the average rate of reaction of hydrogen = -0.00153 mol/Ls, it is negative because it measures the rate of disappearance of the reactants.
2) From chemical reaction: n(Hâ) : n(NHâ) = 3 : 2.
c(NHâ) = 2 ¡ 0.23 mol/L / 3.
c(NHâ) = 0.153 mol/L.
the average rate of reaction of ammonia = 1/2 ¡ (0.153 / 50 s).
the average rate of reaction of ammonia = 0.00153 mol/L¡s.