The equation that describes the reaction between Na and O2 is as follows: 4Na + O2 ......> 2Na2O
Using the periodic table: molar mass of Na = 23 grams molar mass of O2 = 2*16 = 32 grams molar mass of Na2O = 2(23) + 16 = 62 grams
From the balanced reaction: 32 grams of oxygen are required to produce 2*62 = 124 grams of Na2O. Therefore, to know the amount of O2 that would produce 75 grams of Na2O, we will simply use cross multiplication as follows: mass of O2 = (32*75) / 124 = 19.35483871 grams
