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In △ABC , AC=12 in. , BC=1.5 in. , and m∠C=63° .  

What is the area of △ABC ?  

Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth

Respuesta :

wolf1728
Using the Side Angle Side Formula
Area = ½ • side 1 • sine (A) • side 2
Area = ½ • 12 * sine (63°) * 1.5
Area = ½ • 12 * 0.89101 * 1.5
Area = 8.01909
Area = 8.02 rounded

The area of Triangle ABC is 8.02 in².

What is the formula for Area of a triangle ?

The area of a triangle can be expressed using the lengths of two sides and the sine of the included angle.

Area Δ = ½ ab sin C.

It is given in the question

In △ABC

AC=12 in.

BC=1.5 in.

and m∠C=63° .  

Area = ½ * AC* BC * sin (C)

Area = ½ * 12 * sin (63°) * 1.5

Area = ½ * 12 * 0.891 * 1.5

Area = 8.019

Area = 8.02 in²

Therefore the area of Triangle ABC is 8.02 in².

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