Calculate the molar concentration of an aqueous solution of NH3 at 10.9%w (d = 950 g L-1).

Molar concentration has units of moles of solute per liter of solution. Given the percent by mass and the density of the solution, we ca easily convert the concentration into molarity as follows:

10.9 g NH3 / 100 g solution ( 950 g / L ) ( 1 mol / 17.04 g ) = 6.08 mol NH3 / L solution

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nikitarahangdaleVT nikitarahangdaleVT · Answer 2 · 2022-03-31T16:26:39+02:00

The molar concentration of an aqueous solution of NH₃ at 10.9 %w is 6.085M.

How we calculate molarity?

Molarity of any solution will be calculated as:
M = n/V, where

n = moles of solute

V = volume of solution

Given that % weight of NH₃ is 10.9%, means 10.9 g of NH₃ is present in 100g of solution.

Density of solution = 950 g / L

Volume of solution = 100g / 950g/L = 0.105 L

Moles of NH₃ = 10.9g / 17.04g/mol = 0.639 moles

Now we calculate the molar concentration of NH₃ as:
M = 0.639mol / 0.105L = 6.085M

Hence molar concentration of NH₃ is 6.085M.

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