Cattastrof3
contestada

Hydrazine (N 2 H 4 )) a rocket fuel reacts with oxygen to form nitrogen gas and water vapor . The reaction is represented with the equation: N 2 H 4 (l)+O 2 (g)—> N 2 (g)+2H 2O(g)

How many grams are needed to produce 96.0g water?

A.) 32.0g N2H4

B.) 48.0g N2H4

C.) 85.4g N2H4

D.) 192.2g N2H4

Respuesta :

Eduard22sly

The mass of hydrazine (Nâ‚‚Hâ‚„) required to produce 96 g of water (Hâ‚‚O) is 85.4 g (Option C)

Balanced equation

N₂H₄ + O₂ —> N₂ + 2H₂O

Molar mass of Nâ‚‚Hâ‚„ = (2Ă—14) + (4Ă—1) = 32 g/mol

Mass of Nâ‚‚Hâ‚„ from the balanced equation = 1 Ă— 32 = 32 g

Molar mass of Hâ‚‚O = (2Ă—1) + 16 = 18 g/mol

Mass of Hâ‚‚O from the balanced equation = 2 Ă— 18 = 36 g

SUMMARY

From the balanced equation above,

36 g of Hâ‚‚O were produced by 32 g of Nâ‚‚Hâ‚„

How to determine the mass of Nâ‚‚Hâ‚„

From the balanced equation above,

36 g of Hâ‚‚O were produced by 32 g of Nâ‚‚Hâ‚„

Therefore,

96 g of Hâ‚‚O will be produced by = (96 Ă— 32) / 36 = 85.4 g of Nâ‚‚Hâ‚„

Thus, 85.4 g of Nâ‚‚Hâ‚„ is needed for the reaction

Learn more about stoichiometry:

https://brainly.com/question/14735801

Otras preguntas