Respuesta :
For the answer to the question above, Â let coordinates of boat B at 10 am at the buoy be (0,0)Â
then co-ordinates of boat A is (3,0)Â
let dist. between A & B be z, then at time t hrs after 10Â
z² = (3+3t)² +(5t)² = 34t² +18t +9,Â
value 112.5 at t = 1.5Â
2z.dz/dt = 2*34t +2*9Â
dz/dt = (34t +9)/zÂ
= (34*1.5 + 9)/√112.5Â
= 5.6569 mphÂ
then co-ordinates of boat A is (3,0)Â
let dist. between A & B be z, then at time t hrs after 10Â
z² = (3+3t)² +(5t)² = 34t² +18t +9,Â
value 112.5 at t = 1.5Â
2z.dz/dt = 2*34t +2*9Â
dz/dt = (34t +9)/zÂ
= (34*1.5 + 9)/√112.5Â
= 5.6569 mphÂ
Hello there.
Related rates fixed buoy? A boat passes a fixed buoy at 9Â
a.m. heading due west at 3 miles per hour. Another boat passes the same buoy at 10Â
a.m. heading due north at 5 miles per hour. How fast is the distance between the boats changing at 11:30Â
a.m.?
 5.6569 mphÂ
Related rates fixed buoy? A boat passes a fixed buoy at 9Â
a.m. heading due west at 3 miles per hour. Another boat passes the same buoy at 10Â
a.m. heading due north at 5 miles per hour. How fast is the distance between the boats changing at 11:30Â
a.m.?
 5.6569 mphÂ