devonknowles
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PLEASE HELP ME> A proton travels at right angles through a magnetic field of 0.025 teslas. If the magnitude of the magnetic force on the proton is 1.8 Ă— 10-14 newtons, what is the velocity of the proton? The value of q = 1.6 Ă— 10-19 coulombs.

A. 1.8 Ă— 105 meters/second
B. 1.8 Ă— 106 meters/second
C. 2.5 Ă— 106 meters/second
D. 3.8 Ă— 106 meters/second
E. 4.5 Ă— 106 meters/ second

Respuesta :

LittleRedMe
F = Bqv so v = F / (Bq)

v = 1.8x10-14 / (0.025*1.6x10-19)

v = 4.5x10^6 metres/second

So the answer is E.
22andriasjaj

E is the Answer hope this helps

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