Answer:
The ratio of moment of inertia of larger sphere to that of smaller sphere = 4
Explanation:
The moment of inertia of solid sphere is given by I = 2/5MR² where M = mass of sphere and R = radius of sphere.
Radius of smaller sphere = D/2
Radius of larger sphere = 2D/2 = D.
Moment of inertia of smaller sphere Iā = 2/5M Ć D²/4 = MD²/10
Moment of inertia of larger sphere Iā = 2/5M Ć D² = 2MD²/5
The ratio of moment of inertia of larger sphere to that of smaller sphere = Iā/Iā = 2MD²/5 Ć· MD²/10 = 10 Ć 2/5 = 4