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3.20-m-long, 500 kgkg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70 kgkg construction worker stands at the far end of the beam.What is the magnitude of the torque about the point where the beamis bolted into place?

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Kazeemsodikisola

Answer:

10,035

Explanation:

Length of the beam is 3.2m

Mass of steel beam is 500kg

Weight of steel =mg

Ws=400×9.8=4900N

Also, man of mass =70kg

Weight of man(Wm)=70×9.8=686N

The weight of the man will act as the middle of the beam

Torque is given as Force ×distance

tnet=Wm×L + Ws×L/w

tnet=686×3.2+4900×1.6

tnet=10,035.2Nm

The net torque about where the beam is bolted is 10,035.2Nm

Check attachment for diagram

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